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p
<
k
+1
Then, from the conditions on
P
2
(see page
),
b
>
x
k
+1
. This gives us that
P
'
3
>
P
2
.
Timothy Lewis
11/12/1997
![[*]](cross_ref_motif.gif)
), b
> xk+1. This gives us that P'3 > P2.